zip.file.extract {utils}R Documentation

Extract File from a Zip Archive


This will extract the file named file from the zip archive, if possible, and write it in a temporary location.


zip.file.extract(file, zipname = "", unzip = getOption("unzip"))


file A file name. (If a path is given, see ‘Note’.)
zipname The file name (not path) of a zip archive, including the ".zip" extension if required.
unzip character string: the method to be used, an empty string indicates "internal".


All platforms support an "internal" unzip: this is the default under Windows and the fall-back under Unix if no unzip program was found during configuration and R_UNZIPCMD is not set.

The file will be extracted if it is in the archive and any required unzip utility is available. It will be extracted to the directory given by tempdir, overwriting any existing file of that name.


The name of the original or extracted file. Success is indicated by returning a different name.


The "internal" method is very simple, and will not set file dates.

This is a helper function for help, example and data. As such, it handles file paths in an unusual way. Any path component of zipname is ignored, and the path to file is used only to determine the directory within which to find zipname.

[Package utils version 2.5.0 Index]